15. June 2016 summation of external angles of n-gon The summation of internal angles of n-gon = (n-2)pi. The summation of external angles of n-gon = Σe(i), where e(i) is an external angle of n-gon, i moves from 1 to n. Then the below holds. Σ(pi-e(i)) = (n-2)pi, Therefore Σe(i) = 2pi. tagPlaceholderTags: math Write a comment Comments: 0

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