quantity of heat
quantity of heat Q is equal to mass m[g] times specific heat c[J/g/K] times temperature difference Δt[K].
Q = mcΔt [J]
letting cΔt be constant, then
Q ∝ m.
heat capacity C is equal to mass m[g] times specific heat c[J/g/K].
C = mc [J/K]
c is constant. then
C ∝ m.
amount of rainfall precipitation
the amount of rainfall precipitation R is equal to mass m[kg] over an area S[m^2] and duration t[hour].
R = m/(St) [kg/m^2/hour]
letting St be constant, then we get
R ∝ m.
, although C and R are intensive variables.