(1/3)^x < 2

Real solution:

(1/3)^x < 2

 

log{(1/3)^x} < log(2)

where log(x) is the natural logarithm.

 

x log(1/3) < log(2)

 

Noting that log(1/3) is negative.

x > log(2)/log(1/3)

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